Chemistry: Concepts and Applications

Chapter 21: Nuclear Chemistry

Problem of the Week

 
<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=gif::::/sites/dl/free/0078617987/179001/ch21_chapter.gif','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (0.0K)</a>
<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=gif::::/sites/dl/free/0078617987/179001/POWsolutions.gif','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (0.0K)</a>

Teachers Notes:
A good Web site for review of nuclear chemistry.

Problem 1:
27Co59 + 0n127Co60

Problem 2:
27Co6028Ni60 + -1e0 + 0γ0

Problem 3:
number of half-lifes (n) = 26.4/5.27 = 5.01 half-lives

Amount remaining = (initial amount)(1/2)n
Amount remaining = (100.0g)(1/2)5.01=3.10 g remaining

Glencoe Online Learning CenterScience HomeProduct InfoSite MapContact Us

The McGraw-Hill CompaniesGlencoe